Place 6/8 after a seven

We know that there are 36 possible combinations on a pair of fair dice, we also know that there are 6 ways to make a 7 and 5 ways each for the six OR eight to be made. Our sample set is only 16 out of the 36 combinations. If we compare the probability of a 6 (5 ways) or an 8 (5 ways) coming up on any roll as compared to the 7 (6 ways), we have a ratio of 10/16, 62.5% ways to win versus 6/16 37.5% ways to lose. In other words if we were to make a place bet on both the 6 & 8 which pays 7 to 6, we can expect to win 62.5% of the time and lose 37.5 % of the time. Which is an exact representation of the true odds. Since the payoff is only 7 to 6, that is the built in edge for the house. The "edge" on the place 6 or eight is approximately 1.51%. I think you'll agree that is one of the best bets on the casino.

So if we made 100 wagers of simultaneously place 6 & 8 (which must be made in $6 increments, $600, $720, $18, $132, etc..) We can expect on a $6 wager on each to win $7, one at a time, not on both simultaneously, 62.5 times which would equal $437.50. We would lose $6+$6=$12 37.5 times which equals $450.00. This $450 loss less the $437.50 wins equals losses of $12.50 for each 100 wagers. But what happens if we can change the expected outcome of 62.5%/37.5% to ANY ratio where we can generate a profit? Or perhaps said another way, can we expect a result other 10/16 vs. 6/16? Given the same 100 wagers and a change of just 1% to 63.5%/36.5% would equal a win of $444.50-$438.00=$6.50. Amazingly a "swing" of $19.00. But that's the question, isn't it? Can we expect over the long term any change of what is expected over the long term. I say we can. Over 10,000 test rolls (which is not very many) I have discovered that a window of opportunity opens and closes on a typical series of dice rolls that when recognized, can be exploited to start the first phase of my strategy. While on each roll of the dice, if we made each wager, we could expect the above stated outcomes of 62.5%/37.5%, if we make the place 6&8 wager immediately after a seven, the expected outcome changes to approximately 65%/35% A huge change of 2.5% which translates to a profit of $35 for every 100 wagers made. In other words we wait for a seven to show then we make the place 6 & 8 bet. What we're betting on is that two "7s" won't show before one 6 or 8 shows. While it is true that each roll of the dice is an independent event, it is also true that the dice do not know whether or not we've made the previous wager. I have found that for some reason the expectation of a subsequent 7 immediately after a seven is less than the 62.5/37.5 expected ratio. I have a spreadsheet that proves this. Try it! You'll see. Roll many games of 100 rolls each, record only 6s, 7s & 8s. You will find that while in a set of 100 rolls, you do get an even distribution of 62.5%/37.5% the "count" of 6's or 8s after the first seven is higher than 62.5% Try with real dice, computer simulations or stand at a live table in a casino. Any way you track it you will see, over the long run that this "window" of opportunity does exist. But then it closes once a 6 or 8 is rolled. Combining this revelation with the correct bankroll and a disciplined money management technique know as up "regress - up & pull", we can expect consistent daily wins of 10%-20% of our bankroll amount. That may not sound like much. But even playing with table limits, we can expect profits of $10,000 per gaming day. We never bet more than 1/100th of our total bankroll on the two 6 & 8 bets following the seven. We then regress, put down our profit and reinvest 50% of our first wager. If we continue to win, we go with a 50% up & pull progression (see table below). Therefore as the 6 or 8 trend continue, we continue to win more and more. And at any time it ends, we have a profit in our pocket. For example: We wait for a seven to show, place a $120 place bet wager on both the 6 & 8. When one of them comes in, we get paid $140. We pull back the $140 plus $120 off one of the bets and split the remaining down to $60 on each. We now have a $20 profit no matter what happens. Which ever of the 6 or 8 comes next, we get paid $70 of which we reinvest $30 and go up to $90 on the one that came in now pocketing $40. We continue this until we hit the table limit or the trend ends. For this size wager we would need a bankroll of $24,000. Since we don't want to play "short", a major winning mechanism of a casinos. And as you can see when that wager is made the "edge" is in our favor. When that window closes, we pull "our" money off and play with the casino's money. That is why I need a large bankroll to play with. Playing with a smaller bankroll means we lay with a greater than 1/100th of bankroll and does not allow for even regressions and progressions. Since anything can happen over the short run this overly large bankroll protects us from short runs of bad luck.

Below is a sample betting progression:

Progression: 150%

Starting Wager: 120

Wins 140 Nets 20

Well good luck, hope to hear from you. Take Care

Flagshipcomm@mail.earthlink.net